An fuel element of Pressurized Water Reactor, in the form of a cylinder with the
ID: 2077158 • Letter: A
Question
An fuel element of Pressurized Water Reactor, in the form of a cylinder with the hole with inside diameter of 14 mm and outside diameter of 24 mm, constructed from Uranium with thermal conductivity of 31 W/m. oC. Both surfaces are covered by stainless steel with the thermal conductivity of 21 W/m. oC. The stainless steel thickness is 0.5 mm. The heat released per unit volume of fuel element is assumed average of 2 x108 W/m3. The fuel element is cooled by the flowing water along inside and outside surfaces of cooling canal. The average cooling water temperature at inside canal is 200 oC and at outside of canal is 220 oC. The cooefcient of convection heat transfer at inside canal is 8200 W/m2. oC and at outside canal is 7800 W/m2. oC.
Determine:
(a) Temperature maximum at the transverse cross section of the fuel element.
(b) The rate of heat transfer on both surfaces.
(c) Temperature maximum at the transverse cross section of the fuel element if the cooling at inside canal is stopped due to some reasons. In this scenario, it is assumed that there is no heat rejection at inside canal.
Explanation / Answer
Solution:-
Given
An fuel element of Pressurized Water Reactor, in the form of a cylinder with the hole with inside diameter of 14 mm and outside diameter of 24 mm, constructed from Uranium with thermal conductivity of 31 W/m. oC.
Both surfaces are covered by stainless steel with the thermal conductivity = 21 W/m. oC.
The stainless steel thickness = 0.5 mm.
The heat released per unit volume of fuel element = 2 x108 W/m3.
The average cooling water temperature at inside canal = 200 oC and at outside of canal = 220 oC.
The coefficient of convection heat transfer at inside canal = 8200 W/m2. oC and at outside canal = 7800 W/m2. oC.
a) Temperature maximum at the transverse cross section of the fuel element = (8200-7800) * (220-200) = 400*20 = 8000
b) The rate of heat transfer on both surfaces = (21*24- 31*14 ) (220-200) = (504-434) *20 = 70*20 = 1400
c) Temperature maximum at the transverse cross section of the fuel element if the cooling at inside canal is stopped due to some reasons. In this scenario, it is assumed that there is no heat rejection at inside canal, yes it is true because in transverse cross section of fuel delta T is always zero.
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