Interactive Learning Ware 18.2 provides one approach to solving problems such as
ID: 2077725 • Letter: I
Question
Interactive Learning Ware 18.2 provides one approach to solving problems such as this one. The drawing shows three point charges fixed in place. The charge at the coordinate origin has a value of q_1 = +7, 60^mu C; the other two have identical magnitudes, but opposite signs: q_2 = -6.40^mu C and q_3 = + 6.40^mu C. (a) Determine the net force exerted on q_1 by the other two charges, (b) lf q_1 had a mass of 1.50 g and it were free to move, what would be its acceleration? (a) Number Units (b) Number UnitsExplanation / Answer
Given that
q1 = +7.6 *10^-6C
q2 = -6.4* 10^-6C
and q3 = +6.4* 10^-6C
a) The electric force on q1 due to q2 is given by
F2= k q1q2/r^2
= (9.0 x 10^9 )(7.6 x 10^-6 C)(6.4 x 10^-6)/(1.30 m)^2
= 0.259 N
The electric fore on q1 due to q3 is given by
F1 = k q1q2/r^2
= (9.0 x 10^9)(7.6 x 10^-6)(6.4*10^-6 )/(1.30 )^2
= 0.259 N
The net electric force along x -axis is
Fx = F2 cos23 - F1 cos23
= 0
The net electric force along y-axis is
Fy = [F1 + F2] sin 23
= 2( 0.298224852 N) sin 23
= 0.202 N
The magnitude of net electric fore is
F = 0.202 N
Direction is f =tan-1[0.202/0]
= 90o
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b) Given that mass of charge q1 is m = 1.5 x 10^-3 kg
The acceleration of the charge q1 is
a = F/m
= (0.202 N)/(1.5 x 10^-3 kg)
= 134.95 m/s2
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