Consider a heavily inductive load with a series resistance R1= 30 ohm and an ind

Question

Consider a heavily inductive load with a series resistance R1= 30 ohm and an inductance L1 = 3 H, connected through a switch to the AC mains supply (120 VRMS). At the instant, the maximum current is flowing, the switch is opened, causing the current to fall to zero in 1 ms. Assuming the current falls linearly, what voltage is present across the inductor? Assuming the voltage supply in the above question is written as V(t) = V_0 cos (omega t), with frequency 60 Hz, what are the first 3 worst-case times to open the switch (i.e. the times that will result in the maximum-amplitude voltage spike across L1)?

Explanation / Answer

4a).. the instantaneous rate of current change (di/dt) is equal to zero because the current is stable the equation tells us that with 0 amps per second change for a di/dt, there must be zero instantaneous voltage across the inductor.

inductor do not have a stable resistance as conductor d. however, there is a definite mathematical relationship between voltage and current for an inductor as follows.

V = L di/dt

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