An artificial pacemaker an cardiac cells to threshold and initiate action potent
ID: 2079544 • Letter: A
Question
An artificial pacemaker an cardiac cells to threshold and initiate action potentials when the pacemaker cells in the heart are working properly. Suppose that the pacemaker provides a current applied as a square wave pulse (for the purposes of this you can consider it to be a step input). The cardiac muscle cell membrane can be modeled as a resistor and capacitor in parallel, as shown below. We want to bring the membrane potential up from -90 mV to the threshold value of -55 mV (after which Na^+ currents open and the action potential begins), so we need to apply a voltage of 35 mV. The value of the membrane resistance is 3.3 times 10^3 ohm and membrane capacitance is 1.5 times 10^-6 F. If we want the increase in voltage to occur within 5 ms, what should be the value of the current applied (I_m)?Explanation / Answer
As per the question C is already at -55mV after applying 35mV( increased from -90mV to -55mV).
Since R and C are in parallel, total current Im is summation of current through R and current through C.
So Im = IR+IC
Step 1: Current through R(IR)= 35mV(applied voltage)/3.3k Ohm
IR= 10.606 uA
Step 2: Current through C (IC)= C dV/dT
dV- Change in voltage -90mV to -55mV(-90mV-(-35mV)=35mV)
dT- time duration for the capacitor voltage change
Capacitor initial charge is -90mV before applying 35mV, its voltage has to change from -90mV to -55mV within 5mS(let us take 4.5mS).
Therefore IC= 1.5u* (35m/4.5m)
IC= 11.67uA
Step 3: so Im = IR+IC
Im = 10.606uA+11.67uA
Im = 22.276uA
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