If bulbs A and B are identical, predict how the potential difference (voltage) a

Question

If bulbs A and B are identical, predict how the potential difference (voltage) across bulb A in Figure 3.5 will compare to the potential difference across the battery. How about bulb B?

A) VA = VB = Vpower supply because voltage in series connection is the same across all elements

B) VA+VB = Vpower supply and VA > VB because A is closer to the positive (high) terminal of the power supply

C) VA+VB = Vpower supply and VA = VB because A and B are identical

D) VA < VB < Vpower supply because actual electron current flows from negative terminal to positive and the voltage drops along the current path

E) VA+VB = Vpower supply and VA = VB regardless of the resistance of A and B because A and B are connected to the same point

You can now explore the potential difference across different parts of a simple series circuit. Consider the circuit shown in Figure 3.5. Please note that the variable DC voltage supply should be used in place of the battery. DC Power Supply PA VPB Figure 3.5: IMPORTANT NOTE: The switch S1 should remain open except when you are making a measurement. It is in the circuit to save the battery. Use the momentary contact switch for

Explanation / Answer

C) Here both bulb are in series so current flowing through it is same.

As both bulb is identical, Resistance of both bulb will also be same.

and voltage across bulb= current * resistance

so voltage drop will aslo be same.

and KVL states that VA+VB= V power supply

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