5 Resistor Combination Puzzle Consider the resistive circuit shown in Figure 1.

Question

5 Resistor Combination Puzzle

Consider the resistive circuit shown in Figure 1. It consists of 5 resistors (100, 220, 270, 330, and 470 Q) and has 5 terminals, labeled A through E. Notice that each resistor is connected to a unique pair of terminals and that the only interconnections are at the terminals of the circuit. Using basic concepts on series and parallel resistors, one could E solve for the resistances between terminals. For example, it's pretty easy to see that the resistance between terminals B and C is just RBC 220 Q. Between Band D we can use series resistance to get RBD B690 2 220 4700. Terminals A to E is a bit harder as we have the 330 Q resistor in 470 parallel with 370 2 (100 270 in series), so RAE 174 Q (to the Figure 1 nearest Ohm). Doing this computation for all terminal Table 1 Inter-terminal resistances, in Ohms. combinations yields the results in Table 1, note that the symmetry of the problem means that only the A 0 306 86 556 174 red entries are unique. B 306 220 690 386 86 220 470 166 556 690 470 636 Now, imagine that this circuit is actually a model of a 5-terminal device and that you can't see inside E 174 386 166 636 0 the dotted pentagon (as suggested by Figure 2). Your task for this assignment will be to solve the reverse problem; for a given matrix of inter terminal resistances, finding a circuit which would yield those ts. Figure 2

Explanation / Answer

Circuit assumption is wrong

If u check for Rbd we are getting minus value

Similarly if u check for Rce = 136 ... from this we can see Rac =Rce +154=390 but given 181

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