A horizontal copper bar slides up and down along two perfectly conducting, frict

Question

A horizontal copper bar slides up and down along two perfectly conducting, frictionless rails. A uniform flux density, B = 1.0 Wb/m^2, is directed into the paper. The length, resistance, and weight of the bar are given as: l = 0.3 m r = 0.5 Ohm W = mg = 1.5 N g = 6.674 N middot m/kg^1 A. What value of V and I are required if the bar is to move upward at a constant velocity of 5.0 m/s? B. How much energy is supplied by the battery in moving the bar 1.0 m? C. What percent of the supplied energy is dissipated by the 0.5 Ohm resistance?

Explanation / Answer

a) F=BIL

B=1 wb/m2

I= ? L=0.3m

F=1.5N

therefore I=F/B*L    ; I=1.5/1*0.3 = 5A

V=I*R      V=5*0.5 = 2.5V

b) Since bar is with constant velocity no energy is required to move the bar

c) 100%

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