A certain periodic signal, as viewed on an oscilloscope, has period of 2 ms. The

Question

A certain periodic signal, as viewed on an oscilloscope, has period of 2 ms. The net positive area in one cycle appears to be greater than the negative area. List five lowest frequencies on a one-sided basis that would probably appear in the spectrum. A certain periodic signal, as viewed on an oscilloscope, has period of 2 ms. The net positive area in one cycle appears to be greater than the negative area. List five lowest frequencies on a one-sided basis that would probably appear in the spectrum.

Explanation / Answer

                               Solution

Q.1

A certain periodic signal, as viewed on an oscilloscope, has period of 2 ms. The net positive area in one cycle appears to be greater than the negative area. List five lowest frequencies on a one-sided basis that would probably appear in the spectrum.

Ans. 1 –

According to question, we have

Time Period T = 2ms.

Hence, frequency f = 1/T = 1(2*10-3) = 500Hz.

As wave is asymmetric with respect to x-axis, all harmonics will be present in the wave. Then,

The five lowest frequencies will be as given below.

0, 500Hz, 1000Hz, 1500Hz and 2000Hz. (Answer)

Thank You.

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