3/10/2018 1. Plast cell is 200 aM solutes Bathing solution is 0 uM solutes 3.Thi

Question

3/10/2018 1. Plast cell is 200 aM solutes Bathing solution is 0 uM solutes 3.This plant cell would , A. This cell would shrivel B. This cell woeld undergo lysis C. This cell would beceme turgid D. Nothing would happen to this eell. A. Cell is hypertonlk and bathing solution is hy potonic B. Cell is hypotonic and bathing solution is hypertonke C. They are both isetonic 2. The products of the Citric Acid Cyele frem oxidate 2. This orgamelle is involved in translation. A. Ribosomes B. Lysosome C. Mitochoadria D. Smooth ER E. Roagh ER ef I glucose are: A. 2Pyruvate, 2NADH, 2ATP B. NADH ATP C. SNADE, 4FADH2, 2ATP,4CO D. 6NADH, 2FADH2, 2ATP, 4 CO2 E. Nome of the above. 6. Glycolysis occars in the 3·The last electron acceptor during the electron transport chain s A. H B. O C. NAD+ and FAD+ A. Ribosemes B. Chleroplasts C. Mitechondria D. Cytoplasm E. Lysosomes E. None of the above.

Explanation / Answer

Answer

1. Option B is the right answer because the osmotic pressure inside the cells is more than the outside of the cells.

2. Option A is the right answer as ribosome helps in translation

3. Option B is the right answer

4. Option C is the right answer

5. Option D is the right answer because the end product of citric acid cycle releases 6NADH+2FADH+2ATP and

4CO2

6. Option D is the right answer

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