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I built a multiloop circuit for a project. The 4.2v is from mini-USB. The 3.7V i

ID: 2082780 • Letter: I

Question

I built a multiloop circuit for a project. The 4.2v is from mini-USB. The 3.7V is a lipo battery. The circuits are A/V Transmitters (LC circuit) which have an impedance of 75 ohms. The resistor is a 470-ohm resistor. I don't think I'm calculating KVL properly and would like some advice on where to move next. I want to calculate the current throughout the circuit without using my ammeter. The two large ovals are copper plates that act as positive and negative terminals. I'm not sure how to incorporate a charging battery as well as the LC circuits. Do I create a loop for each separate circuit? Thank you for any help

0-754 t7 : 1, 75 , 75" 75 , 75 S" 709. ey 4av----+ 75SL 75su | | 75R | | 7sul / 7ssz | | 75 75/L ) 175n 4.av 4b mA 90 mA ey18.75-a+470S2 : 4ss.g.Q 3.7v 4.av-47b.QTI -18.75-a-3 7V-0 TI-LA 4.av-470L-V6,75Ta=0 / : a

Explanation / Answer

Hello,

As voltage across each 75 ohm resistor is 3.7 V, so current flowing through each 75 ohm resistor = (3.7/75)= 49mA.

so total current in external circuit= 49m*4= 0.197 A.

let's assume that current is i2 = 0.197 A.

Apply KVL to first loop: 4.2-470*i1-3.7=0

Thus i1= 1.06 mA.

Current through (supplied by) "3.7V" battery = i2 - i1 = 0.19594 A

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