A Low Pass first order instrument has a time constant of 20ms. Find the frequenc
ID: 2083441 • Letter: A
Question
A Low Pass first order instrument has a time constant of 20ms. Find the frequency in hertz of the input at which the output will be 93% of the dc output. Find the phase angle at this frequency Discuss some of the possible problems involved in elastic-resistance strain gage sensors and their solutions Calculate and sketch a curve for the radiant output of the skin at 300 k at 2000, 3000, 5000, 10,000and 20,000 nm attached is my answer, Please answer questions 2 and 3
please type the answer, no hand writting
VoCS).JNRc It)("cou !Vol yW))- A Co) 14, at -Shin p0 -a734 l-t(5 eo-1996(3 ed rs 14.96 13 so p-se anda 21, S 66 2(C. A--+ AExplanation / Answer
Ø tan-1
V0(S)=Vi(S)/(1+jRC)
V0(j) =Vi(j)/(1+j(/c))
=Vi(j)/(1+(/c)2)
|V0(j)|=A/(1+(/c)2).........................(1)
DC output: =0
|V0(0)|=A/(1+(0/c)2)
c=1/RC=1/(20*10-3)=50 rad/sec
from the question & eq(1)
0.93A=A/(1+(/c)2)
0.93A=A/(1+(/50)2)
=19.7613 rad/sec
f=/2=19.7613/2*=19.7613/2*3.14=3.145Hz
Phase angle Ø=-tan-1(/c)=-tan-1(19.7613/50)
Phase angle Ø=-21.565°
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.