Can you write a detailed solution, so i can understand, please? We define a Matl

Question

Can you write a detailed solution, so i can understand, please?

We define a Matlab function as follows: function y = myfunc2(x, n0) N = length(x); XX = fft(x, N); YY = XX .* exp(-j*2*pi*n0*(0:N-1)/N); y = ifft(YY, N); end a) Given x = [12 0 1 0 0], predict what would happen if we type y = myfunc2 (x, 2) b) Given x = [1 2 0 1 0 0], predict what would happen if we type y = myfunc2 (x, -2) c) Given x = [1 2 0 1 0 0], predict what would happen if we type y = myfunc2 (x, 25) Note that you are not being asked to write these programs, just to predict the answer based on your understanding of what the program is doing.

Explanation / Answer

now see first you have defined the function

y=myfunc2(x,n0)

you have start by writing "function y"

and then you have mentioned

N

XX

YY

y

and then you have end the function

and make sure you should save the function with its own name

i.e.myfunc

now after saving the function in the directory where you stored other programe

you can also save the programe their in the same directory where you are storing the function

now when you are

writting

x=[1 2 0 1 0 0]

y=myfunc2(x,2)

here you are calling the function in the programme where now x will be the defined array and n0=2

and then matlab will call the function and it runs the function for given below that means

now what happens

say x=[1 2 0 1 0 0]

y=myfunc2(x=[1 2 0 1 0 0],n0=2)

inside the function what happens

N=length(x) it will find the length of total array that means how many element =6;

XX=fft(x,N) it will do the fast fourier algorithm for N point since already there is six element so it will not do any zero padding suppose x has a 4 element and N=6 then N point FFT will add additional two zeros to the signal x and then perform the FFT

YY=XX.*exp(-j*2*pi*n0*(0:N-1)/N);it will multiply the function with the exponential function here in the exponenial term you can see the (0:N-1) term that means it creates the array of exponential term with k=0,1,2,.....N-1 and YY also become the array thats why .* is given between XX and exponential term to multiply element by element of array

Y=ifft(YY,N) do the inverse fft of the signal

now for every value of x it will do the same

hope u understand

since it is written no need to use the code just to understand

so i have just explained you

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