cylindrical capacitor whose cross section is shown below has inner and outer rad

Question

cylindrical capacitor whose cross section is shown below has inner and outer radii of 5mm and 15mm. if V (p=5mm) = 100 volts and V (p=15mm)=0 volts, calculate E at p=10mm and surface charge density on plates. let e_r=2.0

conductor of uniform cross-section has a voltag nsity, J, of the current flowing through it is 2.2 he material and determine which of the conduc capacitor whose cross section is shown belo respectively. Vips 5 mm) 00 volts and 10 mm and p- on the plates. Let Er 2.0. 100 V 15 mm capacitor with square plates is filled with 2

Explanation / Answer

E = change in voltage/change in distance

= (100-0)/(5-15)

= -10 v/meter square

Now, electric field will remain constant through out the surface as there is no time varying field.

Also, Electric field= surface charge density/(2* e_r)

hence, surface charge density = -40

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.