3-Phase RC Phase Sequence Indicator circuit where Load 1 = Load 2 = 100 Ohms, X_

Question

3-Phase RC Phase Sequence Indicator circuit where Load 1 = Load 2 = 100 Ohms, X_cap = -j100 Ohms (C = 31.831uF, 50hz signal) in Wye connection [ See circuit below ]

This circuit is used for Phase Sequence Indication, but how does the 0.27 ratio between Iload1 and Iload2 come about?

When I calcuate the individual currents using standard equations for a Wye connection they're all identical in magnitude at different angles.

Any help would be appreciated!

(Load_1) (Load-2) 2.4A 2.0A 1.6A 1.2A 0.8A 0.AA 0.0A Load 2 0.4A 0.8A 1.2A 1.6A 2.0A 2-4A SINE(0141.4 50 0 0 0) Load 1 100 31.831H SINE(0 41.4 50 0 0 120) 100 Vc SINE(0 141.4 50 0 0-120) tran 0 100m 0 0ms 10ms 20ms 30ms 50ms 60ms 70ms 80ms 100ms

Explanation / Answer

The graph you are getting is wrong actually ,magnitude should be same but may be phase shifted.

While drawing circuit in any software, for 3 phase supply you must use the 3 phase supply block not 3 single phases block. May be you have taken 3 single phase supply at different different angle ,instead of it use the 3 phase supply block. Hope so your result may come true.

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