Why can\'t a diode pass a large current when is reverse biased? Inside the deple

Question

Why can't a diode pass a large current when is reverse biased? Inside the depletion region the electric field gats larger and then smaller-this bell curve works as a mirror and traps carriers so they are not available to carry current. Reverse current is limited by generation in quasi-neutral region which extends slightly beyond depletion distance and is never large. Built in electric field blocks current from crossing depletion region in reverse direction Charge carriers entering depletion region are instantaneously depleted and can't make it to the ohmic contacts. Why can a diode pass a large current from the p-type to n-type region. Forward biasing the diode raises the barrier and allows exponentially more carriers to bypass the depletion region. Forward biasing the diode lowers the barrier and allows exponentially fewer carriers to be annihilated so they don't have to cross the depletion region. Forward biasing the diode lowers the barrier and allows exponentially more carriers to cross the depletion region. Forward biasing the diode raises the barrier and allows exponentially more carriers to cross the depletion region. Why can the diode pass a large current in the reverse direction when biased below a well defined breakdown voltage (Va

Explanation / Answer

The answer to the first question is

3.built in electric field blocks current because as we give reverse bias the width of depletion region increases so result in increase of electric field

Answer to the 2nd question is also

3.forward bias lowers the barrier and allows exponentially more carriers to cross the depletion region

Answer to the third question is

2.at large enough reverse bias carrier entering the depletion region can gain enough kinetic energy to generate additional carrier which gains enough energy to create additional carrier

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