How would one connect a hmc5883l to a an arduino uno in order to allow it to det
ID: 2085480 • Letter: H
Question
How would one connect a hmc5883l to a an arduino uno in order to allow it to detect an object and bring an autonomous vehicle closer to it so that a magnetic sensor( which I also need to connect) would be able to sense if it's a magnetic material. The autonomous vehicle needs to pick up some magnetic material. How would one connect a hmc5883l to a an arduino uno in order to allow it to detect an object and bring an autonomous vehicle closer to it so that a magnetic sensor( which I also need to connect) would be able to sense if it's a magnetic material. The autonomous vehicle needs to pick up some magnetic material.Explanation / Answer
Magnetometer HMC5883L measures the direction and magnitude of the Earth’s magnetic field and hence is used for low cost compassing and magnetometry.
It measures the Earth’s magnetic field value along the X, Y and Z axes from milli-gauss to 8 gauss.It can be used as a compass to find direction or to find the direction of heading of a device.
It makes use of I2C protocol for communication with a microcontroller. Earth’s magnetic field values along the X, Y and Z axes can be found by reading values from addresses of certain registers using I2C communication.
GND: Connect ground to this pin.
SCL: Connect serial clock out from master device to this pin.
SDA: Connect serial data line from master device to this pin.
DRDY: Data Ready status signal pin output from module to master device.
The components of Earth Magnetic Field (Hx, Hy) are parallel to the earth’s surface and are used in determining the compass direction. Only the X and Y components of the earth’s field are used in determining the azimuth angle, or the compass direction.
Azimuth (x=0, y<0) = 90
Azimuth (x=0, y>0) = 270
Azimuth (x<0) = 180 - [arc tan(y/x)] *180/
Azimuth (x>0, y<0) = - [arc tan(y/x)] *180/
Azimuth (x>0, y>0) = 360 - [arc tan(y/x)] *180/
Which gives Azimuth angle () from 0 to 360 degree in X direction relative to the magnetic north.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.