True/False questions( I want to know why it is True or False, need details) A, A

ID: 2085796 • Letter: T

Question

True/False questions( I want to know why it is True or False, need details)

A, Assembly language directive "DS32 4" allocates 16 bytes in memory.

B. Assembly language directive "DS8 3" allocates 3 bytes in memory and initializes them with value 0x00.

C. Assembly language directive "DS16 1" allocates 4 bytes in memory.

D. Assembly language directive "DS8 4" allocates 4bytes in memory and initilaizes them with value 0x00.

E. The instruction MOV. B #145, &0x0300 requires 3 words to be encoded.

F. Assembly language directive "DS32 2" allocate 8 bytes in memory.

G. Assembly language directive "DS16 4" allocates 8 bytes in memory.

H. Assembly language directive "DS8 2" allocates 2 bytes in memory and initializes them with value 0x02.

I. The instruction MOV. B #45, &0x0300 requires 2 words to be encoded.

J. Assembly language directive "DS16 2" allocates 4 bytes in memory.

K. Assembly language directive "DS16 4" allocates one 16-bit word in memory and initializes it with value 4.

L. Assembly language directive "DS8 2" allocates one byte in memory and initializes it with value 2.

A - TRUE.

As DS32 means 32 bit of data allocation. 32 bit = 4 byte.

So DS32 4 = 4 × 4 bytes = 16 bytes.

B- FALSE

DS8 means 8 bit or 1 byte of data allocation.

So DS8 3 means 1×3 bytes = 3 bytes. As they are used for uninitialized memory space. They initialize that with 0×3

C- FALSE

DS16 means 16 bit or 2 bytes of memory allocation.

So DS16 1 means 2 ×1 = 2 bytes. Hence 4 bytes is wrong.

D- FALSE.

DS8 4 means 1 × 4 = 4 bytes. It initializes with 0×4.

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