In this coding of MATLAB, the given gear ration only have 2, and to find wheel s

Question

In this coding of MATLAB, the given gear ration only have 2, and to find wheel speed,w1 and w2, are based on the gear ratios (gear1, gear 2), transmission reduction(R_reduct) and the cycle is cycle(i,10) = (cycle(i,2)/(pi*dia))*60; .
How can I modify this coding to calculate for 4 wheel speeds by means to have 4 different gear ratio, and the condition is not based on the engine max but the current speed? As in the example below, it only has two gear ratio to find two wheel speed by making a condition based on the engine max either to be greater or lesser.

??????????????????????????????????????????????????????????????????????????? max3400 E idle 800: ??????????????????????????????????????????????????????????????????????????? %Maximum Engine Speed (RPM) %Engine idle speed (RPM)

Explanation / Answer

% based upon minimizing the rotational speed of the hydraulic components, % thereby minimizing the power flow through them.

function [gear] = Gear(i, cycle, gear1, gear2, gear3, gear4, R_Reduct, E_current)

w1 = cycle(i,10)*R_Recluct*gear1;

w2 = cycle(i,10)*R_Recluct*gear2:

w3 = cycle(i,10)*R_Recluct*gear3:

w4 = cycle(i,10)*R_Recluct*gear4:

if w1 < E_current

gear = gear1;

elseif w2 < E_current

gear = gear2;

elseif w3 < E_current

elseif gear = gear3;

elseif w4 < E_current

gear = gear4;

else

gear = -1

sPrintf (‘Engine Speed Reached at Time Step: %i Requested engine speed: %i Current engine speed: %i’, i, w4, E_current)

end

if cycle(1,10) == 0;

gear = 0;

end

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