1. complete medium- 100% 2. minimal medium with galactose- 2.1% 3. minimal mediu

Question

1. complete medium- 100%

2. minimal medium with galactose- 2.1%

3. minimal medium with ampicillin and glucose- 9.2%

4. minimal medium with ampicillin, galactose and biotin- 4.5%

In a transformation experiment, bacteria containing amp(R), bio(+) and gal(+) are used to transform an amp(S), bio(-) and gal(-) recipient. The results are shown above. I have expressed the number of colonies as a percent, so we don't need to do calculations. What is a possible map for these three genes, amp, bio and gal?

Explanation / Answer

Donor strain = amp(R), bio(+) and gal(+)

Recipient strain = amp(S), bio(-) and gal(-)

Genes that are transferred first show high recombination frequency. Similarly, Genes that are transferred last show low recombination frequency.

Lowest recombination frequency = 2.1%. So, galactose is the last gene in the linear sequence.

Highest recombination frequency = 9.2%. So, amp and glu are the first genes in the linear sequence.

The recombination frequency is intermediate when biotin is provided in the media.

Possible order of genes:

Amp-Glucose-bio-Gal

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.