What happens to the electric field between two conducting plates when an uncharg

Question

What happens to the electric field between two conducting plates when an uncharged metal slab is placed between them? Does it change or remain the same? I'm really confused on this concept. Also, when the same plates are connected to a battery, and the metal plate is again inserted between them, how does the electric field between the plates (but outside the slab) change? For this one, my thoughts are because it's connected to a battery, the voltage difference is constant. Because voltage difference = electric field x distance, and distance is smaller (due to width of metal plate) then the electric field must get larger to keep voltage difference the same. Is this correct?

Explanation / Answer

FOLLOW THIS a) E? =0 as inside the metal electric field is zero... metal slab face which is near to +vely charged plate will have ?? sufrace chage distribution and the face which is near to -vely charged plate will have +? surface charge density . b) W=?q0V0 c)no nothing will be changed ....new charge distribution of metal slab give zero electric field outside the slab ..so their is no change due to introduction of slab d)no ...their is no change in charge distribution on metal plate ..

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