I have a circuit with 3 loops, 5 resisters, and 3 batteries Resistor <?xml:names
ID: 2090286 • Letter: I
Question
I have a circuit with 3 loops, 5 resisters, and 3 batteries
Resistor <?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /?>
Resistance [?]
Battery
Voltage[V]
1
161
1
9
2
180
2
4.5
3
300
3
6
4
300
5
820
my circuit equations are as follows
Loop
C Equation
1
2
-I_2 R_5-?_1-?_2+I_3 R_3-I_2 R_4=0
3
?_1+I_2 R_5+I_2 R_4-?_3+I_1 R_2+I_1 R_1=0
I have complete confidence in my circuit equations but I have not been able to calculate my values
.for the current I_1, I_2, or I_3.
Can someone not only help me find the values but show me exactly how it was done.
Resistor <?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /?>
Resistance [?]
Battery
Voltage[V]
1
161
1
9
2
180
2
4.5
3
300
3
6
4
300
5
820
Explanation / Answer
after putting the vlaues and rearraging the equations become
10.5 = 341 I1 + 300 I3 --------------(1)
13.5 = 300 I3 - 1120 I2 -----------------(2)
3.5 = -1120 I2 - 341 I1 -------------------------(3)
and also I1 = i2 +I3
putting the value of I1 in 1 we get
10.5 = 341 I2 + 641 I3 -----------------(4)
solving 4 adn 2 we get
I3 = 0.0199 A
putting it in 2 and dolving ofr I2 we get
I2 = -0.0067 A
so I1 = 0.0132 A
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