i only have one question at the bottom, and i already found the rest, so can som

Question

i only have one question at the bottom, and i already found the rest, so can someone help me on the last probleem please?

A Diffraction Grating:Laser light is shown through a diffraction grating with a line density of 300 lines/ mm . The 2nd order maximum is measured to be 2.30 m away from the center on a screen that is 4.52 m from the diffraction grating.

What is the wavelength of the laser?

i found the wave length = 756

How many laser dots are visible on the screen (assuming that the wall is large enough)?

i found the laser dots to be 9

3.What is the total distance between the two first order maxima on the wall?

i found also, the total distance = 2.10m

1. so, my question is,If the laser were replaced with a 60 5nmlaser instead, at what distance from the central maximum would the second order be located?

Explanation / Answer

i found your answers were slightly.deviating than mine........

y = m lambda L/d

2.3 = 2*lambda*4.52/(1.0E-3/300)
lambda = 8.48E-7 m

2) d sin theta = m lambda
max m at theta = 90
m = d/lambda = (1.0E-3/300)/8.48E-7=3.93
answer 2m + 1 = 7

3) same as ditance from center to m=2 so
2.3 m
4)
y = 2*605E-9*4.52/(1.0E-3/300)=1.64

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