A woman of mass m = 58.0 kg sits on the left end of a seesaw-a plank of length L

Question

A woman of mass m = 58.0 kg sits on the left end of a seesaw-a plank of length L = 4.77 m, pivoted in the middle as shown in the figure. First compute the torques on the seesaw about an axis that passes through the pivot point. Where should a man of mass M = 68.4 kg sit if the system (seesaw plus man and woman) is to be balanced? m Find the normal force exerted by the pivot if the plank has a mass of mpl = 13.9 kg. N Repeat part (a), but this time compute the torques about an axis through the left end of the plank. m

Explanation / Answer

a)
58*9.81*4.77/2 = 68.4*9.81*x
x=2.0224

b) sum forces in the y
N - 58*9.81 - 68.4*9.81 - 13.9*9.81 = 0
N=1376.3

c) sum torques about left end
1376.2*4.77/2 - 13.9*9.81*4.77/2 - 68.4*9.81*x =0
x=4.407

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