Consider a 10 ohm resistor in series with a 5 ohm and 10 ohm parallel combinatio

a) R=10+5*10/5+10 R=13.33 ohms b) I=V/R =9/13.33 I=0.675 A c) P=VI =9*0.675 P=6.1 W d) P=I^2*R =0.675^2*13.33 P=6.1 W

ID: 2092560 • Letter: C

Question

Consider a 10 ohm resistor in series with a 5 ohm and 10 ohm parallel combination. Assume the emf is 9 V.

1) What is the total resistor, in ohms, of the circuit?

a) 25

b) 15

c) 13

d) 6.7

2) What is the total current, in amps, of the circuit?

a) .67

b) .36

c) 1.3

d) 0.1

3) What is the power output of the emf?

a) 11.7 W

b) 3.2 W

c) 10 W

d) 6.1 W

4) What is the total rate of energy dissipation in the circuit?

a) 11.7 W

b) 6.1 W

c) 10 W

d) 9.7 W

If you could show me your work I would really appreciate it!!

Thanks ahead.

R=10+5*10/5+10

R=13.33 ohms

I=V/R =9/13.33

I=0.675 A

P=VI =9*0.675

P=6.1 W

P=I^2*R =0.675^2*13.33

P=6.1 W

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