A solid disk rotates in the horizontal plan at an angular velocity of 0.067 rad/

Question

A solid disk rotates in the horizontal plan at an angular velocity of 0.067 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.10 kg m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all of the sand is in place, what is the angular velocity of the disk?

Please show work, and express in apprpriate units.

Explanation / Answer

Iw = (I+Is)w'

0.1*0.067 = (0.1+0.5*0.4^2)*w'

w' = 0.037rad/s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.