I\'m lost and lab is in an hour. Please help! Thanks so much. 4. Solve the follo
ID: 2093666 • Letter: I
Question
I'm lost and lab is in an hour. Please help! Thanks so much.
4. Solve the following equations (2 equations with 2 unknowns) for x in terms of: m, g, h. Refer to Appendix D: Math
Review if necessary. (10 pts.)
6x = 9y
5y2 = mgh
5. Solve the following equations (2 equations with 2 unknowns) for x in terms of: m, M, g, h. (10 pts.)
mx = (m + M)y
0.5(m + M)y2 = (m + M)gh
6. Solve Eq 9-6 and Eq 9-7 (2 equations with 2 unknowns) for v1 in terms of: m, M, g, h. (10 pts.)
m v1 = (m + M) V2 (Eq 9-6)
(m + M) V2
2 = (m + M)gh (Eq 9-7)
Phys 223/224 ~ Pre-Lab 9
Conservation of Energy and Linear Momentum
78
7. You shoot a ball, m = 50.0 g, into a catcher, M = 200.0 g; the center of mass rises 15.0 cm. Calculate v1. Refer to
your answer for Question 5. (20 pts.)
8. You will fire the spring gun 3 times from the first detent and measure the change in height of the (pendulum + ball) for
each shot. Write the equation for the change in height of the first shot. (20 pts.)
9. Write the equation for the uncertainty of the change in height of the first shot. Refer to Appendix A Page A-6 if
necessary. (10 pts.)
BONUS OPPORTUNITY!
5 point bonus on your report if the following is completed correctly. (You may want to record these equations in your lab
notebook for use during the procedure.) Show your work on a separate sheet of paper.
1. Solve Eq 9-6 and Eq 9-7 for v1 in terms of the following quantities: m, M, g, h.
2. Your equation for v1 should have a sum, (m+M). Define this sum as m
Explanation / Answer
only allowed one question per post.. I answered two
4)
y = 6x/9 = 2x/3
so
5*(2x/3)^2 = m g h
20 x^2/9 = m g h
x = sqrt( 9 m gh/20)
5)
y = mx/(M + m)
then
0.5 (m+M) (m x/(M+m))^2 = (m + M) g h
0.5 m^2 x^2/(M+m)^2 = g h
x^2 = 2 (M+m)^2 gh/m
x = sqrt(2 (M+m)^2 gh/m)
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