A 0.6 kg piece of Al at 645 degrees C is combined with a 0.1 kg cube of ice at -

Question

A 0.6 kg piece of Al at 645 degrees C is combined with a 0.1 kg cube of ice at -15 degrees C in a thermally isolated calorimter cup of negligible specific heat. What is the equilibrium temperature the mixture eventually reaches?

Specific heat of water = 4.184 kJ/kg-K

Specific heat of ice = 2.05 kJ/kg-K

Specific heat of Al = 1.9 kJ/kg-K

Heat of fusion and melting point of water = 334 kJ/kg @ 0 degrees C

Heat of fusion and melting point of Al = 400 kJ/kg @ 660 degrees C

Heat of vaporization and boiling point of water = 2257 kJ.kg @ 100 degrees C

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Explanation / Answer

0.6 x 1.9 x (645 - T) = 0.1 x (15 - 0) x 2.05 + 0.1 x 334 + 0.1 x (T) x 4.184

T = 33.71 - 735.3 / [-( 1.14 + 0.4184)] = 450.20 degreeeC

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