Switch S, shown in the figure below, is closed after having been open for a long

Question

Switch S, shown in the figure below, is closed after having been open for a long time. What is the initial value of the battery current just after switch S is closed? A What is the battery current a long time after switch S is closed? A What are the charges on the plates of the capacitors a long time after switch S is closed? Q5muF = mu C Q10 mu F = mu C Switch is reopened. What are the charges on the plates of the capacitors a long time after switch S is reopened? Q5 mu f = mu C q10 mu f = mu C

Explanation / Answer

a) Capacitance is short initially

so equivalent resistance = 10 + 4.615

= 14.615

I = 50/14.615 = 3.42 A

2) after long time capacitor is open circuit

equivalent resistance = 10 + 15 +12 + 15

= 52

I = 0.961 A

3) potential difference across capacitor = 0.961 *(27)

=25.96 V

charge = 259.6 uC

4)potential difference across capacitor = 0.961 *(27)

=25.96 V

charge = 259.6 uC

5) 0

6)0

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.