Problem: Given po=600 kg/m^3, A =5.7 m^2, V0=0.60m^3, pf=1000kg/m^3 Find h Equat

Question

Problem: Given po=600 kg/m^3, A =5.7 m^2, V0=0.60m^3, pf=1000kg/m^3 Find h

Equating the buoyant force=weight of displacement fluid=pf*g*h with objects weight=po*g*vo=600*9.8*0.60N=3.53*10^3N (h=3.53*10^3/1000*9.8*5.7m) m=0.063m

Alternatively, with po/pf = 0.600, 60% of the rafts volume is submerged or 0.6 of its total height V0/A = 0.105 m i.e., 0.6 Vo/A =0.6*0.6/5.7 m=0.063m

Problem. Find the maximum number of people, each 75 kg in mass, that could stand on this raft without wetting their feet?

Explanation / Answer

N*75*9.81 + 600*9.81*0.6 = 1000*0.6*9.81

N = 3.2

Hence, 3 persons

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