(a) The captain of a ship grabs hold of the wheel with one hand a distance of 0.

Question

(a) The captain of a ship grabs hold of the wheel with one hand a distance of 0.255m from the axis of rotation to adjust the rudder. Assuming that he is pushing with a force of 27.6N perpendicular to axis of rotation, what is the magnitude of the torque? (b) Later on the wind is calm and the oars are necessary to move the boat. A rower with his arms outstretched initially has the oar at 72.1o from the direction he is pulling. If he pulls with a force of 89.7N, then what is the magnitude of the initial torque for an oar that is grabbed a distance of 1.65m from the pivot point?

Answers for both in Kg m^2/s^2

Explanation / Answer

a)

torque = fr = 27.6*0.255 = 7.038 N-m

b)

initial torque = Frsin 72.1 = 89.7*1.65*sin72.1 = 140.84 N-m

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