Two identical masses are connected through a massless string across a massless f

Question

Two identical masses are connected through a massless string across a massless frictionless pulley. The portion of the string between the pulley and the mass on the right is held horizontal. Initially both are at rest and the tension in the string is zero. The mass on the right is released and begins to swing downward. At what angle (Theta) will the mass on the inclined plane begin to slide if the coefficient of static friction between the mass and the plane is 0.5? The angle (Phi) is equal to 66degrees.

Explanation / Answer

mgsin33+mg*.5*cos33=mgsintheta theta=sin^-1(.95)

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