O 10.) 18 pts total] Two blood group alleles, L and L., have a co-dominant relat
ID: 209668 • Letter: O
Question
O 10.) 18 pts total] Two blood group alleles, L and L., have a co-dominant relationship. A man and a woman, both in the MN blood group, are planning to have two children. [4 pts] What is the probability that the two children will have either MN or M blood type? (Give 1 answer. not 2.) a) 2. b) (4 pts] What is the probability that both of these two children will be girls with the MN blood type? 0 11.) 17 points] In mice coat (R) is dominant over smooth (r). A rough one. (Do not assume these parents are homozygbus.) The genes are independently assorting. The offspring are 29 rough black; 31 rough smooth white. What are the genotypes of the parents? blac k mouse is bred to a rough-white white: 1I smooth black: and 9 P.BbRrExplanation / Answer
A mam XY with blood group MN (allele L^M L^N) and woman with same blood group will have children with following probability
1.Top row female parent and left side row male parent. When both parent are heterozygous then theTable shows that 1 female will have M and other Female has MN blood group possibility. In the same way 1 male will have MN group and other will have N group. probability of 2 children with mn group will be 2/4 =1/2.
2.Out of two girls produced one will have MN blood group and their probability will be 1/2.
Lm - X Ln-X Lm- X LmLm - group M /XX female LmLn- group MN/ XX -female Ln-Y LmLn- group Mn / XY male LmLn - group N/ XY - maleRelated Questions
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