Your boss asks you to construct a special resistor made of two metals. Metal 1 i

Question

Your boss asks you to construct a special resistor made of two metals. Metal 1 is iridium and metal 2 is uranium. The iridium is 25 cm long with a square cross section of 3.0 mm on a side. The uranium is 40 cm long, also with a square cross section of 3.0 mm oil a side. The two metals are fused together at one of their 3.0times3.0 mm2 ends, making a conductor that has a total length of 65 cm. What is the electrical resistance measured between the ends of the composite rod, under the assumption that no additional resistance occurs at the point where the rods are fused? State your source for the electrical resistivities of the two metals.

Explanation / Answer

resistivity of uranium = 0.28 *10^-6 ohm -m

resistivity of iridium = 0.05 *10^-6 ohm m

R of uranium = rho L/A = 0.28 *10^-6 * 0.25/0.003*0.003 = 7.77 *10^-3 ohms

R of iridium = 0.05*10^-6 *0.4 /0.003 *0.003 = 2.22 *10^-3 ohms

total resistance R =R1 + R2 = 9.99 10^-3 ohms =

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