A 1.050 kg air-track glider is attached to each end of the track by two coil spr
ID: 2100284 • Letter: A
Question
A 1.050 kg air-track glider is attached to each end of the track by two coil springs. It takes a horizontal force of 0.700 N to displace the glider to a new equilibrium position, x= 0.190 m.
Find the effective spring constant of the system.
Answer: 3.68 N/m
The glider is now released from rest at x= 0.190 m. Find the maximum x-acceleration of the glider.
Answer: 6.67x10^-1 m/s^2
Find the x-coordinate of the glider at time t= 0.450T, where T is the period of the oscillation. Need Help with this one
Explanation / Answer
c)The position can be give by:
x=0.19Cos(2pi*t/T)
x=0.19*Cos(2pi*0.45)=-0.181m ( Use 3 significant figures because it is so in the question too). This is the correct answer.
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