1) Two small loudspeakers are separated by a distance of d = 5.9 cm, as shown in

Question

1) Two small loudspeakers are separated by a distance of d = 5.9 cm, as shown in the figure below. The speakers are driven in phase with a sine wave signal of frequency 12 kHz. A small microphone is placed a distance L = 1.4 m away from the speakers on the axis running through the middle of the two speakers, and the microphone is then moved perpendicular to the axis. Where does the microphone record the first minimum and the first maximum of the interference pattern from the speakers? The speed of sound in air is 343 m/s. y1st min =

2)

Explanation / Answer

wavelength = v/f =343/12000 =0.029 m = 2.9 cm 1st minimum at d*sin(theta) = wavelength/2=>sin(theta) = wavelength/2d =>sin(theta)=2.9/2*5.9 => (theta)1 min = 14.24 degrees X(min) = 1.4*tan 20 = 0.509 m =50.9 cm 1st max, dsin(theta)=wavelength =>(theta)1 max =29.34 degrees X (max) = 1.4*tan 29.34 = 78.69 cm

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