Quesiton #1: A 5kg mass initially moving at 4m/s is sliding up a 5.0 degrees ram

Question

Quesiton #1:

A 5kg mass initially moving at 4m/s is sliding up a 5.0 degrees ramp. It is acted upon by the force F(s) = 2s+0.5s^2. Find its speed when it has travelled 10m along the ramp.

Question #2:

Find the maximum compression of the spring by the 5kg mass after the coeffiecient of restitution (e=0.93) nearly elastic collision. Assume the spring is initially uncompressed. Note the ramp is rough. Treat the masses as point objects.

Please answer both questions above for full rating!

Explanation / Answer

1). F(s=2) = 6 N a= F/m = (6-mg*sin 5)/5 =0.346 m/s2 v^2 -u^2 =2as => v^2 = 16 +2*0.346*2 => v= 4.17 m/s 2). velocity at the time of reaching spring = v' v'^2 -4^2 = 2*(g sin 40- 0.1*9.8* cos40) *[(10/sin 40)-3] => V'^2 -16 = 139.38 => v' =12.47 m/s e = velocity of separation/velocity of approach => 0.92 = v/12.47 => velocity of separation= 11.47 m/s decrease e in K.E. of block = increase in P.E. of spring => 0.5*3* [(12.47)^2 -(11.47)^2] =0.5 *250*x^2 => x= 0.536 m

Related Questions

Navigate

• Browse (All)
• Browse Q
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.