A cannon shots a 1000 kg ball 60 degrees above hortizontal. During the first sec

Question

A cannon shots a 1000 kg ball 60 degrees above hortizontal. During the first second (1s) the ball is accelerated inside the cannon barrel and experiences a net force of 50000 N towards the barrel opening (being pushed by gases produced by burning gun powder, no friction). Calculate: 1)Velocity of the ball when it leaves the cannon
A cannon shots a 1000 kg ball 60 degrees above hortizontal. During the first second (1s) the ball is accelerated inside the cannon barrel and experiences a net force of 50000 N towards the barrel opening (being pushed by gases produced by burning gun powder, no friction). Calculate: 1)Velocity of the ball when it leaves the cannon

Explanation / Answer

let velocity be v so Vx=v*0.5 Vy=0.866*V

acceleration=50000/1000=50

so velocity=50*1=50m/sec

so Vy=43.3

time taken=2*Vy/g=8.827 sec

MAx height=Vy^2/2g=95.56 m

distance=25*8.82=220.5m

the ball reaches with same velocity as it left the cannon but only the direction of vertical component is reversed

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