A heat engine absorbs 2440 J of heat from a hot reservoir and expels 640 J to a

Question

A heat engine absorbs 2440 J of heat from a hot reservoir and expels 640 J to a cold reservoir. When it is run in reverse, with the same reservoirs, the engine pumps 2440 J of heat to the hot reservoir, requiring 1800 J of work to do so. Find the ratio of the work done by the heat engine to the work done by the pump. A heat engine absorbs 2440 J of heat from a hot reservoir and expels 640 J to a cold reservoir. When it is run in reverse, with the same reservoirs, the engine pumps 2440 J of heat to the hot reservoir, requiring 1800 J of work to do so. Find the ratio of the work done by the heat engine to the work done by the pump.

Explanation / Answer

work done by heat engine = (2440-640) = 1800J (Using 1st Law of thermodynamics)

Work done by pump = (2440-1800) = 640J (Again using 1st Law of thermodynamics)

So, the ratio is: 1800/640 = 2.8125

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