Problem # 51 from section 29.6 [NOT IN SOLUTIONS] Here is what is written in thi

Question

Problem # 51 from section 29.6 [NOT IN SOLUTIONS]

Here is what is written in this homework problem:

In an experiment designed to measure the Eearth's magnetic field using the Hall effect, a copper bar 0.500 cm thick is positioned along an east-west direction. Assume n = 8.46 X 10^(28) electrons/m^(3) and the plane of the bar is rotated to be perpendicular to the direction of B(vector). If a current of 8.00 A in the conductor results in a Hall voltage of 5.10 X 10^(-12) V, what is the magnitude of the Earth's magnetic fiels at this location?

I am interested in understanding your solution and therefore learning so please show me the steps of the solution.

Thank you in advance for your effort.

Explanation / Answer

The magnetic field can be found from the Hall effect voltage:

delta VH = I B / n q t

B = ( n q t delta VH ) / I

= (8.46 * 10^28 * 1.6 * 10-19 * 0.00500 * 5.10 X 10-12 ) / 8

= 4.31 * 10-5 T

= 43.1 mu T

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