In a summer internship with a manufacturing technology company, you are asked to
ID: 2101506 • Letter: I
Question
In a summer internship with a manufacturing technology company, you are asked to help design a disk brake system for an industrial rinding wheel. Disk brakes operate using pressurized oil to push outward on a piston. The piston, in turn, presses a brake pad against a spinning wheel that needs to be stopped. Actually, there are two oil-piston-pad set-ups designed to squeeze the spinning wheel, one from each side. The grinding wheel has mass 15 kg, is 26 cm in diameter, and has a mximum spinning rate of 900 rpm. The design needs to be able to stop the wheel from maximum speed to zero in 5.0 sec. The material you are considering for the brake pad has coefficient of static friction 0.8 and kinetic friction 0.6 with the wheel. You realize that you should figure out how pressurized the oil needs to be. After making some measurements, you find that hte pistons that actuate the brake pads have diameter 2.0 cm, and that the distance at which the brake pads contact the wheel can be assumed to have anaverage value of 12 cm from the axle.
I'm pretty much completely lost, all I've done so far is draw pictures and write down a list of variables I know. I don't really know what I'm even looking for. Any help would be appreciated. I'm looking for an explanation of how to actually approach this problem, not just a straight up answer please. I don't learn from an answer alone. Thanks!!
Explanation / Answer
the distance travelled by the wheel in t = 5 s is
S = ut + (1/2)at2
u = r1 * w where
r = ((26 - 12)/2) cm = 7 cm = 7 *10-2 m and w = 900 rpm = 900* (2?/60)radian/s=94.2
94.2radian/s
a = (u2/r)
we know that
v2 - u2 = 2?kaS
or v = [u2 + 2?kaS]1/2
?k = 0.6
the acceleration of the wheel is
a = (v/t)
or a = ([u2 +2?kaS]1/2/t)
the oil pressure needed is
P = (F/A) = (m * a/? * r2)
put
m = 15 kg and r = 26 cm = 26 * 10-2 m
to get the answer
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