3. In the cross utAR\' 9. x F. gm 9rg SOS the first geneace too close together t

Question

3. In the cross utAR' 9. x F. gm 9rg SOS the first geneace too close together to infer their order by timed mating. After mating, bacteria are plated on medium containing and ace 300 bacterial colonies are What are the 4 possible genotypes of bacteria that can grow on this plate? Write them in the table below (1 pt a. # of Colonies b. The 300 colonies are replica-plated onto a plate that contains Ery, but does not contain the nutrients Arg or Aro, 252 of the colonies grow What genotype(s) are these colonies? Based on this information, start to fill in column 2 of the above table. (1 pt) When the same 300 colonies are replica-plated onto a plate that contains EO and 253 colonies grow. What genotype(s) are these colonies? Based on this information, continue to fill in column 2 of the above table. (1 pt c. d. When the same 300 colonies are replica-plated onto a plate that contains E and Ace 279 colonies grow, what genotype(s) are these colonies? Based on this information, continue to fill in column 2 of the above table. () Based on the information in b-d, how many colonies of the remaining genotype exist? 1 pt) e. f. Based on the data from a-d. determine the gene order and genetic distances of ana grg, and (2 g)

Explanation / Answer

Part a-

The four possible genotypes would be-

aro+ arg- ery+                                  =253

aro- arg+ ery+                                  =279

aro- arg- ery+                                   =300

aro+ arg+ ery+                                 =252

Here each genotype must contain the erythromycin gene because if this absent then bacteria die by the antibiotic effect of Erythromycin.

part b-

Then this must be aro+ arg+ ery+ because if the plates were not have Arginine and aromatic amino acids (aro) then the bacteria should have these genes to make Arginine and aromatic amino acids by self.

Part c-

This must be aro+ arg- ery+.

Part d- this is the genotype aro- arg+ ery+.

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