A series RLC circuit consists of a 102 ohm resistor, a 12.0 mH inductor, and a 0

Question

A series RLC circuit consists of a 102 ohm resistor, a 12.0 mH inductor, and a 0.600 nF capacitor. It is connected to an oscillator with an rms voltage of 11.0 V. Part A What is the power supplied to the circuit if omega=0.5*omega_0? Part B What is the power supplied to the circuit if omega=omega_0? Part C What is the power supplied to the circuit if omega=2*omega_0? A series RLC circuit consists of a 102 ohm resistor, a 12.0 mH inductor, and a 0.600 nF capacitor. It is connected to an oscillator with an rms voltage of 11.0 V. Part A What is the power supplied to the circuit if omega=0.5*omega_0? Part B What is the power supplied to the circuit if omega=omega_0? Part C What is the power supplied to the circuit if omega=2*omega_0? A series RLC circuit consists of a 102 ohm resistor, a 12.0 mH inductor, and a 0.600 nF capacitor. It is connected to an oscillator with an rms voltage of 11.0 V. Part A What is the power supplied to the circuit if omega=0.5*omega_0? Part B What is the power supplied to the circuit if omega=omega_0? Part A What is the power supplied to the circuit if omega=0.5*omega_0? Part B What is the power supplied to the circuit if omega=omega_0? Part C What is the power supplied to the circuit if omega=2*omega_0? What is the power supplied to the circuit if omega=2*omega_0?

Explanation / Answer

total Z = 102 +j(wL - 1/wC)

current = 11/Z =11/(102 +j(wL - 1/wC))

power = real( I^2 *Z) = real(11^2 /(102 +j(wL - 1/wC)))

w0 = value of w when imaginary part of Z = 0

hence w0 = 1/sqrt(L*C)= 372.68 kHz

now putting values:

part A

power = real[121/(102 - j(6708.14))] = 2.74 *10^-4 Watt.

part B

power = 121/102 = 1.186 Watt

part C

power = real[121/(102 +j(6708.14))] = 2.74 *10^-4 Watt.

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