Two converging lenses (a) Locate the final image relative to the lens on the rig

Question

Two converging lenses

(a) Locate the final image relative to the lens on the right.

(b) Obtain the overall magnification.

(c) Is the final image real or virtual?

(e) Is it larger or smaller?

Explanation / Answer

for left lens; 1/v -1/u =1/f => 1/v -1/(-12.1) =1/9.1 => v = 36.703 cm m1 = v/u = 36.703/(-12.1) = -3.033 for right lens; 1/v -1/u =1/f => 1/v -1/(36.703-18.3) = 1/6.2 => v = 4.638 cm m2= v/u = 4.638/(36.703-18.3) = 0.252 a). final image will be 4.638 cm to the right of the lens on the right. b). total magnification = m1*m2 = -0.764 c).real d). inverted e). smaller

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.