Identify the unknown isotope X in the following decays. Identify the unknown iso
ID: 2103690 • Letter: I
Question
Identify the unknown isotope X in the following decays.
Identify the unknown isotope X in the following decays. 230Th rightarrow X + alpha Enter the isotope symbol using a superscript for the mass number (e.g., enter ^(238)U for 238U). 35S rightarrow X + e- + Enter the isotope symbol using a superscript for the mass number (e.g., enter ^(238)U for 238U). X rightarrow 40 K + c+ +v Enter the isotope symbol using a superscript for the mass number (e.g., enter (238)U for 238U). 24Na rightarrow 24 Mg + e- + rightarrow X + gamma Enter the isotope symbol using a superscript for the mass number (e.g., enter ^(238)U for 238U).
Explanation / Answer
In part A; Th loses an alpha particle, which has two protons and two neutrons. So, thorium losing two protons and two neutrons gives Radium with 88 protons and 138 neutrons. In part B; Sulphur loses an electron and an anti-neutrino. So, effectively; one neutron is converted into a proton, with the loss of electron not affecting the mass in any way. So, you get a Chlorine with 17 protons and 18 neutrons. In part C; I think 41 Ca 20 should be the answer. This is because, 41 Ca loses a positron which has no mass and a neutrino with a 1 neutron mass. In part D; 24 Na loses an electron and an anti-neutrino which gives 24 Mg 12. After that, gamma is nothing but energy. So, X is the same as 24 Mg 12.
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