Two thin lenses with a focal length of magnitude 10 cm, the first diverging and

Question

Two thin lenses with a focal length of magnitude 10 cm, the first diverging and the second converging, are located 7.88cm apart. An object 1.90mm tall is placed 17.5cm to the left of the first (diverging) lens. How far from this first lens is the final image formed?(In cm) Is the final image real or virtual? What is the height of the final image? (in mm) Is it erect or inverted? Two thin lenses with a focal length of magnitude 10 cm, the first diverging and the second converging, are located 7.88cm apart. An object 1.90mm tall is placed 17.5cm to the left of the first (diverging) lens. How far from this first lens is the final image formed?(In cm) Is the final image real or virtual? What is the height of the final image? (in mm) Is it erect or inverted? Two thin lenses with a focal length of magnitude 10 cm, the first diverging and the second converging, are located 7.88cm apart. An object 1.90mm tall is placed 17.5cm to the left of the first (diverging) lens. How far from this first lens is the final image formed?(In cm) Is the final image real or virtual? What is the height of the final image? (in mm) Is it erect or inverted?

Explanation / Answer

(1/u)+(1/v)=1/f

or (1/17.5)+(1/v)=-1/10

or v=-6.36 cm

o u=7.88+6.36

=14.24

so,

1/14.24 +1/v =1/10

or v=33.58 cm

a)33.58+7.88

=41.46 cm

b)real

c)h'=1.9*(6.36/17.5)*(33.58/14.24)

=1.63 mm

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