A 976 kg car is going 25 m/s and the driver has to slam on his brakes to prevent

Question

A 976 kg car is going 25 m/s and the driver has to slam on his brakes to prevent an accident. Assume that a total of 24.7 kg of iron in the brake pads and rotors absorb the heat produced by the friction between the brake pads and rotors. After the car has stopped, what is the change in temperature of the brake pads and rotors? You do not have to enter units for this problem, only the numeric value to two decimal places A 976 kg car is going 25 m/s and the driver has to slam on his brakes to prevent an accident. Assume that a total of 24.7 kg of iron in the brake pads and rotors absorb the heat produced by the friction between the brake pads and rotors. After the car has stopped, what is the change in temperature of the brake pads and rotors? You do not have to enter units for this problem, only the numeric value to two decimal places

Explanation / Answer

mass of the car m = 976 kg

energy = 0.5 mv^2 = 0.5 x 976 x 25^2 = 305000 J

from

305000 = mc(dT)

305000 = 24.7 x 449 (dT)

change in tempetature dT = 27.5 celsius degree

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