A spring, of negligible mass and which obeys Hooke\'s Law, supports a mass M on

Question

A spring, of negligible mass and which obeys Hooke's Law, supports a mass M on an incline which has negligible friction. The figure below shows the system with mass M in its equilibrium position. The spring is attached to a fixed support at P. The spring in its relaxed state is also illustrated. Mass M has a value of 205 g. Calculate k, the spring constant. Tries 9/99 Previous Tries The mass oscillates when given a small displacement from its equilibrium position along the incline. Calculate the period of oscillation. Tries 3/99 Previous Tries

Explanation / Answer

angle with horizontalÂÂ

tan(theta) = 50/110 = 0.4545

sin(theta) = 0.4137

stretching of spring = 50-20 = 30 cm

balancing the force

kx= mgsin(theta)

k * 3 x 10^-1  = 205 x 10^-3 * 9.81 * 0.4137

k = 2.680.N/m

w = 2pi/ sqrt(k/m)

= 5.508 s

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.