After a hard rain, you walk out into the parking lot and notice an oil sheen on

Question

After a hard rain, you walk out into the parking lot and notice an oil sheen on top of a puddle of water. when viewed from directly above, the light reflected off the puddle is a bright red which you estimate to be a wavelength of 690nm. the index of refraction of water is n=1.33 and the index of refraction of the oil is n=1.47.

I understand that the light reflected from the top of the oil has a phase shift. and that the light reflected off the bottom of the oil from the water does not have a phase shift.

What is the minimum thickness of the oil?

What wavelength of light is transmitted into the water most effectively?

I do not know how to account for the one phase shift is it the same equations if both had been inverted?

Explanation / Answer

a) 2 d = (lamda/n)/2 ==> d = lamda/4n = 690e-9/4/1.47 = 1.173*10^-7 m

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.