At time t(0) = 0, 6 x 10^22 electrons in a short neutral vertical cooper wire ar

Question

At time t(0)= 0, 6 x 10^22 electrons in a short neutral vertical cooper wire are accelerated very briefly upward at 2 x 10^8 m/s^2, by a power supply which is not shown. Detectors of electric and magnetic fields are placed at location A, 10 meters from the wire, as shown in the diagram. (The diagram is not to scale; the length of the bar is only a few centimeters.) What is the magnitude of the electric field at location A at time t1 when detectors at A first detect electric and magnetic fields.

1.66 x 10^4 V/m is correct. Could you explain how to solve this?

Explanation / Answer

Use the Formula of Radiative Electric Field..... as ((1/ 4*pi*Epsilon)*(6*10^22*1.6*10^-19*cos(30)*2*10^8))/(10*(3*10^8)^2) = 1.66 * 10^4

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.