1) The diameter of the aluminum cylinder is measured to be: (4.935 ±0.003)cm. Th

Question

1) The diameter of the aluminum cylinder is measured to be: (4.935 ±0.003)cm. The hanging mass (paint bucket and 5kg) for a Mechanical Equivalent of Heat experiment is recorded as (5.2977 ±0.0002)kg. The aluminum cylinder is turned 234 times. Calculate the work done cranking the aluminum cylinder.

2) The amass of the aluminum cylinder is (207.8 ±0.1)g. Once the cylinder is turned through the numbers of turns as described in Problem 1, the cylinder's change in temperature is (11.2 ±0.6) °C. Determine the amount of heat that entered the cylinder.

3) Based on the results of Problem 1 and Problem 2, determine the value for the Mechanical Equivalent of Heat as determined in the experiment described. How does this compare to the accepted value?

Explanation / Answer

Since you want the volume in cm, it's easiest to convert everything from mm to cm right away.So the diameter is 3.90 cm, and the length is 3.11 cm.Now the equation to find the volume of the cylinder is (pi)*(r^2)*(h)If you think about it this way, the area of a circle is (pi)*(r^2) and you stack a lot of them on top of each other to give it volume, so therefore, the volume depends on the area of the circle and how high you stacked it.In this case, it's (3.14) * (1.95^2) * (3.11) = 37.1 cm^3To fi

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